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    Wrench

Wrenches

A linear force ff acting on a rigid body at point pp creates a torque (moment) mm that can be represented in a reference frame {a}\{a\} as:

ma=ra×fam_a = r_a \times f_a

With:

  • maR3m_a \in \mathbb{R}^3: Torque or moment
  • raR3r_a \in \mathbb{R}^3: Point of action (of rigid body)
  • faR3f_a \in \mathbb{R}^3: Force acting on the rigid body

Wrench

The moment and the force can be combined in a 6-dimensional vector (like with twists) called wrench (or spacial force).

Fa=[mafa]R6F_a = \begin{bmatrix} m_a \\ f_a \end{bmatrix} \in \mathbb{R}^6
  • FaR6F_a \in \mathbb{R}^6: Wrench (spacial force)
  • maR3m_a \in \mathbb{R}^3: Torque or moment on rigid body
  • faR3f_a \in \mathbb{R}^3: Force acting on rigid body

A wrench that has a zero linear component is a pure moment

Sum of Wrenches

If multiple wreches act on a rigid body, the total wrench is the sum of all wrench vectors. The wrenches need to be represented in the same frame.

Fa=Fa1+Fa2++FaN=[ma1fa1]+[ma2fa2]++[maNfaN]F_a = F_{a1} + F_{a2} + \cdots + F_{aN} = \begin{bmatrix} m_{a1} \\ f_{a1} \end{bmatrix} + \begin{bmatrix} m_{a2} \\ f_{a2} \end{bmatrix} + \cdots + \begin{bmatrix} m_{aN} \\ f_{aN} \end{bmatrix}

Conversion between Frame Representations

  • FsF_s: spacial wrech
  • FbF_b: body wrech
From Body Frame to Space Frame
Fs=AdTbsT(Fb)=[AdTbs]TFbF_s = Ad_{T_{bs}}^T(F_b)= [Ad_{T_{bs}}]^TF_b
From Space Frame to Body Frame
Fb=AdTsbT(Fs)=[AdTsb]TFsF_b = Ad_{T_{sb}}^T(F_s)= [Ad_{T_{sb}}]^TF_s

Literature

Notes taken from:

Modern Robotics: Mechanics, Planning, and Control by Kevin M. Lynch and Frank C. Park, Cambridge University Press, 2017



  • Category

  • Mechanics

  • Tags

  • Robotics

  • Created

  • 4. January 2021


  • Modified

  • 8. April 2022